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Hackers have released a jailbreak for iOS 10.1.1 and iPhone 7

Developer Luke Todesco intends to release a jailbreak for iOS 10.1.1 for all Apple devices, including the smartphones of the latest generation iPhone 7. About this he wrote in his microblog.

The developer, who previously worked on the iPhone and iPad, has promised to release a ready exploit for iOS 10.1.1. Anyone who wants to see on the home screen the Cydia icon, it is recommended to stay on this OS version. Exploit based on a vulnerability discovered by a team of Project Zero Team.

“Chances are, I will take part in the project of “0” and will write a full jailbreak on top of it. Stay on iOS 10.1.1, especially the owners of iPhone 7,” wrote Todesco.

The hacker added that his jailbreak will not open sortnum, that is, they will not be able to use third-party programmers.

“I’m not going to open exploit, he will be protected from third party interference. The code is almost unreadable, but you have nothing to lose,” added the developer.

In September of this year Todesco announced the successful hacking of the iPhone 7. No details about how the jailbreak he did not, but confirmation has placed the smartphone with installed Cydia 1.1.26 (en-us).

Currently, iTunes 10 is not available for any of the compatible devices. “Ten” is considered the most impregnable Apple from the point of view execute arbitrary code. At least, that positions the IOS company. To strengthen the protection of OS have involved the best experts in the information security field, including hackers and the creators of exploits.

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Luca Todesco told about the possibility of jailbreak for iOS 10.1.1 in early December. He recommended that anyone who expects to jailbreak an iPhone or iPad, to refrain from installing iOS 10.2, which closed critical gaps, or to revert to 10.1.1, if the device is already updated.

We will follow the development of iOS 10 and the iPhone 7. Follow us on Twitter to not miss the release!

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